From the “Things to do when bored” thread.
So, I was bored and decided to make a simple quadratics equation (x+1)(x+3) into something far more less hard.
(x+1-y)(x+3+y)+2y=2(x-y)(y+5x)+5(x^4+y)-xy-16
Solve for x.
Anybody think they can solve it? Me and Ed aren’t even sure you can find x, but methinks it’s possible.
Somebody tell me what x is.
Happy algebra
Keven, the most beared 16 year old you’ll ever see.
As the tree said to the lumberjack, “I’m very doubtful that x can be found.”
Ed
It may not be possible by direct solution, I think you want to use some sort of approximation like the Modified Euler or Runga Kutta to find the solutions.
Yeah, I agree with this statement, although I care not to elaborate on my reasonings for reaching this conclusion.
I have no idea what you’re talking about.
x = -0.4606697204
Are you sure about that?
How did you get that?
Ed
It doesn’t.
x is an interger.
Just a little help.
im one of those guys that can figure out any equation in his head in a split second.
actually i typed it into my calculator and thats what it came up with.
damn calculators.
You mean grizzly 16 year old?
There are 4 values of x which, with y=0 satisfy the equation . Two of the roots are complex, two are non integer, the real roots, as a clue for you, lie in this range
-1.5 < x < +1.5, (unless my fag packet algebra has an error). Now go solve it.
Nao
4
Ehh, what do you mean by solve for x? Find the roots?
x=768
x=530
x=unicycle
x = y
multiply both sides by x
x^2 = xy
add x^2 to both sides
2(x^2) = x^2 + xy
subtract 2xy from both sides
2(x^2) - 2xy = x^2 - xy
factor it
2(x^2 - xy) = 1(x^2 - xy)
divide both sides by (x^2 - xy)
2 = 1
NOTHING IS REAL
2(wheels)=1(bike) however
me > you
Ed
If you divide both sides by (x^2 - xy) you will be dividing both sides by zero. This will not do.
X = Whatever you want it to be, imagination is bliss